Wheels and Distance

1. The diameter of the wheel is 5.8 cm.

2. The circumference is 5.8∏ cm.

3. It will go 2 rotations.

4. It will travel approximately 36.4 cm.

5.

Trial 1: 35 cm

Trial 2: 35.3 cm

Trial 3: 35.2 cm

6. 

i. It did not go the same distance because the robot is not 100 % accurate all the time.

ii. 35.2 cm

iii. We averaged the distances to see how precise and accurate the measurements were and so that we could calculate average error.

7. 3.30% error

8.

i.Yes, it was close.

ii. Yes, since the actual distance was close to the predicted distance, it supports the hypothesis. We were able to estimate how far the robot would travel.

iii. No. Many more trials are needed to validate the hypothesis and make sure it is true in all cases.

9. The back wheels started behind the line and then went two rotations. To measure from the line to the back of the robot would be to leave out the length of the robot in the distance measurement, therefore producing false results.

10. 3.1 cm

11. 3.1∏ cm

12. 2 rotations 

13. 19.48 cm

14. 

Trial 1: 19.1 cm

Trial 2: 19.2 cm

Trial 3: 19.4 cm

15. 19.23 cm

16. 1.28 % error

17.

i. Yes, they were about right.

ii.  No. We need to test more sizes of wheels and different robots to make sure that the hypothesis is true in all cases. We also need other scientists to validate our results. More that two sets of trials is needed to prove a hypothesis.

iii. It could be proven by testing multiple times and with different wheels. Other scientists need to validate our results. 

18. 

i. Our results support the hypothesis because while the results did not exactly match the predicted distance, they were very close.

ii. According to our results, I would say that the hypothesis is correct.

iii. We measured the diameter of the wheel and then found the circumference by multiplying by pi. To get the distance traveled, we multiplied the circumference by the number of rotations. Then we tested our predicted distance by running the robot and measuring the distance traveled three times. We then repeated the experiment for a different size wheel. Everything did validated Dr. Turner's hypothesis

19. 

i. 18.2 cm per rotation.

ii.  10= 5.8∏(x)

     x = .54 rotations(360 degrees)= 197.57 degrees

iii. 20= 5.8∏(x)

    x = 1.1 rotations(360 degrees) = 395.14 degrees
iv. 30 = 5.8∏(x)
    x = 1.65 rotations(360 degrees) = 592.72 degrees
v. To get x, multiply the circumference (18.2cm) by the number of rotations. Then multiply by 360 degrees.
vi. No, it would not work for any robot. The robot must have wheels and have the same specifications.
20. An advantage to controlling the distance in centimeters would be that we can easily see how far a centimeter is. It is much harder to visualize distance in terms of rotations.
21. The wheels are attached to the motors. If the motor turns once, the wheel will turn once.
22.
i. 14.45 cm
ii. No. The robot is not very accurate, as our previous experiments show. It will be close, but not exact. 
23. The robot will travel four times as far as it would with the old wheels.
24. 
i. 4.2∏(2) = 26.4 cm
  26.4 = 3∏ (x)
  x= 2.80(360) = 1008.41 degrees
ii. The hub only wheels have no traction.
iii. Since the wheels have no traction, the robot will not move correctly and probably not go the desired distance.
25. You must tell the team the new diameter and the desired distance. If you do not communicate this information, the robot will not run the required distance.
26.
i.d∏ (1 rotation) = 7.85
  2.5 cm in diameter
ii. 2.5∏(2 rotations)= x
   x = 15.7 cm 
27. 
i. 2040/360 = 5.667 rotations
 d∏ (5.667 rotations) =65 cm
      d = 3.7 cm
ii.  1020/360 = 2.8333 rotations
    d∏ (2.8333 rotations) = 65 cm
     d = 7.3 cm
28. 9600/360 = 26.667 rotations
     2.7∏ (26.667 rotations) = x
     x = 226.2 cm 
     3 in (2.54cm/ 1 in) = 7.62 cm in diameter
     7.62∏(x) = 226.2 cm
     x = 9.45 rotations(360 degrees) = 3420 degrees